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how i can solve this square of binomial (3z+2k)2?

Deb12 Mathematics 2 10

how i can solve this square of binomial (3z+2k)2?

Posted by Deb12 | Posted at Mar 26, 2000 | Categories: Mathematics

Answers

Jadeandrews260
Jadeandrews260

You can solve this by the 1st identity which is (a+b)=a^2+b^2+2ab (3z)^2+(2k)^2+2*3z*2k =9z^2+4k^2+12kz

Mar 26, 2000 01:50
Gracie216
Gracie216

[latex](3z+2k)^2=(3z)^2+2cdot 3zcdot 2k +(2k)^2 = 9z^2 + 12kz +4k^2[/latex]

Mar 26, 2000 01:58

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