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# how do you solve 3x-2 divided by 8=x/4-1 ? the answer is x= -6 but how do you solve it?

cebanadrian2003
Mathematics
2 4

how do you solve 3x-2 divided by 8=x/4-1 ? the answer is x= -6 but how do you solve it?

#### Answers

BettieZumbrunnen

(3x - 2) / (8) = (x/4) - 1 Multiply each side by 8 : 3x - 2 = 2x - 8 Add 2 to each side: 3x = 2x - 6 Subtract 2x from each side: x = -6 .

Mar 26, 2000 01:52

[latex] frac{3x-2}{8}= frac{x}{4-1} [/latex] [latex] frac{3x-2}{8}= frac{x}{3} [/latex] Cross, Multiply : [latex]3(3x-2) = 8x[/latex] [latex]9x-6 = 8x[/latex] [latex]9x - 8x - 6 = 0[/latex] [latex]9x - 8x = 6[/latex] [latex]oxed{x = 6}[/latex] Note : Remember this cross multiply formula : [latex] frac{a}{b} = frac{c}{d} ,,,,,,,,, o ,,,,,,,,,(a imes d) = (b imes c)[/latex]