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how do you describe the roots of 9y² - 6y + 5 = 0?

mrsdarcy1981 Mathematics 2 7

how do you describe the roots of 9y² - 6y + 5 = 0?

Posted by mrsdarcy1981 | Posted at Mar 26, 2000 | Categories: Mathematics

Answers

yassautumn
yassautumn

[latex]9y^2- 6y + 5 = 0 9y^2-6y+1+4=0 (3y-1)^2+4=0 (3y-1)^2=-4 yin emptyset [/latex]

Mar 26, 2000 01:17
Gracie216
Gracie216

[latex]9y^2 - 6y + 5 = 0 a=9, b= -6 , c=5 Delta =b^2-4ac = (-6)^2 -4cdot9cdot 5 = 36 -180 = -144 If Delta <0, then roots are imaginary (non-real)[/latex]

Mar 26, 2000 01:24

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